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TW Catalogue EN Int. 03-2015

44 03/2015 11 4/6 Example glulam beam, GL24h beam width b = 120 mm beam height h = 800 mm cross section lef,1 = 190 mm = (160 mm + 30 mm) Part safety factors wood, GL M = 1,25 steel M = 1,1 reaction Vd = 94 kN (KLED middle) kmod = 0,8 lateral (FRd = 12,9 kN/1,1 = 11,7 kN; buckling decisive) requ. number nerf = spacing and II to grain, one above the other a1 = 90 mm > 40 mm  II to grain, from edge a1,c = 50 mm > 40 mm  L to grain, one above the other a2 = 60 mm > 40 mm  L to grain, from edge a2,c = 30 mm > 24 mm  eff. length lef,2 = 50 mm + 90 mm + 330 mm = 470 mm lateral = 0,96  1,00  plate thickness d = 2,70 · FRd = 2,70 · 11,7 = 9,2 → 10 mm c,90,d kc,90 · fc,90,d 94000 N · 1,25 190 mm · 120 mm · 1,75 · 0,8 · 2,7 = = 1,36  1,00 → reinforcement necessary! Vd – Fc,90,d FRd 94 kN – 68;9 kN 11,7 kN = = 2,15 → 4 pcs. = 68,9 kNRc,90,d = 120 mm · 190 mm · 1,75 · 0,8 · 2,7 1,25 · 1000 800 160 120 GL24h,120/800 mm 94kN 45° 800 160 330 l = 470 120 GL24h, 120/800 mm 94kN 120 306030 160 50 90 20ef,2 Given Loading Proof of the support pressure without reinforcement N mm2 N mm2 Vd lef,2 · b · fc,90,d 94000 N · 1,25 470 mm · 120 mm · 0,8 · 2,7 = N mm2 General remarks: – All calculations must be verified and signed off by the planner in charge of the project before the work is performed. Proof in the plane of the fastener point Steel plate compression compression distances load-bearing capacity bearing surface area Shearing pressure reinforcement with WT-T-8,2 x 332Reinforcement WT / WR Lateral compression reinforcements Technical documentation and data sheets 11. 4403/2015 5090 20ef,2

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